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Home » 3^3 = 27 \text combinations - AIKO, infinite ways to autonomy.

3^3 = 27 \text combinations - AIKO, infinite ways to autonomy.

📅 May 3, 2026 👤 scraface

May 03, 2026

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So only $(1,2), (2,1)$; $(3,0)$ invalid, $(0,3)$ invalid
Also $(1,2), (2,1)$ — wait, also $(3,0)$ no, $(0,3)$ no
$(1,2), (2,1), (3,0)$ no — also $(1,2), (2,1), (3,0)$ — only if $i=3,...
Also $i=1, u=2$; $i=2, u=1$; $i=3, u=0$ — invalid
So valid: $(1,2), (2,1), (3,0)$ — no, $u=0$ invalid
Wait: $i + u = 3$: pairs are $(1,2), (2,1), (3,0), (0,3)$ — only first...
$(1,3,1), (2,2,1), (3,1,1), (1,2,2), (2,1,2)$
Total favorable: $6 + 18 + 6 + 9 + 9 = 48$
Question: A pharmacologist is designing a trial involving 6 different...
Solution: Total number of ways to assign 6 distinct drugs to 6 patient...

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