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Home » \(a^2 = 4\), \(b^2 = 21\) is not possible - AIKO, infinite ways to autonomy.

\(a^2 = 4\), \(b^2 = 21\) is not possible - AIKO, infinite ways to autonomy.

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 \Rightarrow 5y = 10 - \frac{200}{23} = \frac{230 - 200}{23} = \frac{30}{23}

📌 \Rightarrow y = \frac{30}{23 \times 5} = \frac{6}{23}

📌 The intersection point is:

📌 \boxed{\left( \frac{100}{23}, \frac{6}{23} \right)}

📌 A traffic congestion index is modeled by \( t^2 - 6t + 8 \leq 0 \). Find the largest value of \( t \) that satisfies this inequality.

📌 t^2 - 6t + 8 \leq 0

📌 t^2 - 6t + 8 = (t - 2)(t - 4)

📌 The roots are \( t = 2 \) and \( t = 4 \). The expression is less than or equal to zero between the roots:

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