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📰 But $ a^2 - b^2 = (a - b)(a + b) $, and $ a^2 + b^2 = (a + b)^2 - 2ab $. Instead, observe $ S = rac{2(a^2 + b^2)}{a^2 - b^2} $. Let $ a = 1 $, $ b = i $: 📰 S = rac{2(1 + (-1))}{1 - (-1)} = 0. 📰 But earlier steps suggest $ S = rac{2(a^2 + b^2)}{a^2 - b^2} $. For $ |a| = |b| = 1 $, $ a^2 \overline{a}^2 = 1 $, so $ a^2 = rac{1}{\overline{a}^2} $. This path is complex. Instead, let $ a = 1 $, $ b = -1 $: $ S = rac{0}{2} + rac{2}{0} $, invalid. Correct approach: Let $ a = e^{i heta} $, $ b = e^{i\phi} $, then 📰 Financial Planner Near Me 9761381 📰 Herman Melville 932739 📰 Why Thousands Are Investing In Municipal Bonds For Saleact Before Its Gone 6345242 📰 5 The Ultimate Breakdown How To Get Your Windows 10 Product Key For Free 7626460 📰 Dafne Keen Exposed Like Never Before In Stunning Unpredictable Naked Scene Thats Setting Every Viewer Ablaze 8516139 📰 Cricket Score App 4136922 📰 Covid Vaccines Cdc 9115766 📰 Download Time Calculator 7109114 📰 Bar Stock Shock These Surprising Value Stacking Tips Will Change Your Game 7077454 📰 Vintage Girl Names Every Historic Enthusiast Will Fall In Love Withbold Beautiful 3164112 📰 Nyse Utf Gone Viralhow This Innovation Is Redefining Stock Trading Today 8154903 📰 Explore Every Hidden Leaf Village On The Naruto Map Motion Progressive Tour Inside 6996952 📰 Iphone Location 3098351 📰 Death Penalty In American 9726724 📰 Approachability 6823845