V_{\text{cone}} = \frac{1}{3} \pi (3y)^2 (4y) = \frac{1}{3} \pi \cdot 9y^2 \cdot 4y = \frac{1}{3} \pi \cdot 36y^3 = 12\pi y^3

Sat, 02 May 2026 17:50:16 +0000

Content under review