As \(t \to 0^+\), \(h(t) \to \infty\), and \(h'(t) = \frac{2t^2 - (1 + 2t)(2t)}{t^4} = \frac{2t - 2(1 + 2t)}{t^3} = \frac{2t - 2 - 4t}{t^3} = \frac{-2t - 2}{t^3} < 0\), so decreasing.

Tue, 05 May 2026 03:48:32 +0000

Content under review