Question: What is the remainder when the sum of three drug trial durations (111, 113, 115 days) is divided by 7?

Mon, 04 May 2026 15:45:25 +0000

**What is the remainder when the sum of three drug trial durations (111, 113, 115 days) is divided by 7?**
Understanding the hidden math behind major drug development timelines is more than a simple calculation—it reflects how progress is measured in real-world medicine. When experts examine trial durations, they often focus on efficiency, safety phasing, and regulatory benchmarks. One intriguing question arises: what is the remainder when the sum of three key trial periods—111, 113, and 115 days—is divided by 7? This calculation reveals subtle patterns in how timelines are structured, offering insight into industry norms without assuming medical expertise. **Why is this question gaining attention among health and research communities?**
In the fast-evolving landscape of pharmaceutical innovation, stakeholders and curious readers increasingly seek transparency. Drug development is not just about length—it’s about timing, feasibility, and predictability. The inclusion of modular, repeatable trial durations plays a role in resource allocation and trial design. When users ask: *What is the remainder when 111 + 113 + 115 is divided by 7?* they’re tapping into a growing interest in decoding clinical processes in digestible terms. The result, 343 divided by 7, yields a clean 0 remainder—making it not only mathematically elegant but culturally resonant in debates about efficiency and cost-effectiveness. **How to calculate the remainder—step by step** First, sum the trial durations:
111 + 113 + 115 = 339 days total.
Next, divide by 7:
339 ÷ 7 = 48 with a remainder of 3.