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number of protons in helium atom - AIKO, infinite ways to autonomy.

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 2r + 2 = (3 + \sqrt{5})r - (3 + \sqrt{5})

📌 2r + 2 = (3 + \sqrt{5})r - 3 - \sqrt{5}

📌 2r - (3 + \sqrt{5})r + 2 + 3 + \sqrt{5} = 0

📌 r = rac{5 + \sqrt{5}}{1 + \sqrt{5}}

📌 Rationalize:

📌 r = rac{(5 + \sqrt{5})(1 - \sqrt{5})}{(1 + \sqrt{5})(1 - \sqrt{5})} = rac{5 - 5\sqrt{5} + \sqrt{5} - 5}{1 - 5} = rac{-4\sqrt{5}}{-4} = \sqrt{5}.

📌 Case 2:** \( rac{r+1}{r-1} = rac{3 - \sqrt{5}}{2} \)

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