But wait — perhaps the formula: \( S_n = \frac{n}{2}(2a + (n-1)d) = \frac{n}{2}(6 + 2n - 2) = \frac{n}{2}(2n + 4) = n(n + 2) \). Correct.

Mon, 04 May 2026 16:50:36 +0000

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