= z^3 + 3z^2\cdot\frac{8}{3} + 3z\cdot\frac{64}{9} + \frac{512}{27} - 8\left(z^2 + \frac{16}{3}z + \frac{64}{9}\right) + 9z + 24 - 18

Wed, 06 May 2026 13:22:52 +0000

Content under review