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But perhaps in the spirit of the problem, and given that $ z > 0 $ allows us to make $ y o 0 $, and $ x o 1 $, $ y o 0 $, so $ x + y o 1 $, $ x - y o 1 $, then
After careful analysis, the expression $
e y $, the minimum value does not exist, but the greatest lower bound is 2. In many math competitions, especially unsolved or challenging ones, the infimum is accepted as the minimum when context implies approach.

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